layout: Do not attempt to activate a split or a fs surface

As long as there is (an already created) surface in a split/fs type of role
there's no point in trying to activate it. Users can mistakenly try to
do that so have some logic in place to avoid it.

Bug-AGL: SPEC-3334

Signed-off-by: Marius Vlad <marius.vlad@collabora.com>
Change-Id: Id9b8e039b6d53fbfb4e310166a91c2cb6a45cb4e

diff --git a/src/layout.c b/src/layout.c
index a09010c..fd01c5b 100644 (file)
--- a/src/layout.c
+++ b/src/layout.c
@@ -551,6 +551,24 @@ ivi_layout_panel_committed(struct ivi_surface *surface)
        surface->view->is_mapped = true;
 }
 
+static bool
+ivi_layout_surface_is_split_or_fs(struct ivi_surface *surf)
+{
+       struct ivi_compositor *ivi = surf->ivi;
+       struct ivi_surface *is;
+
+       if (surf->role != IVI_SURFACE_ROLE_SPLIT_H &&
+           surf->role != IVI_SURFACE_ROLE_SPLIT_V &&
+           surf->role != IVI_SURFACE_ROLE_FS)
+               return false;
+
+       wl_list_for_each(is, &ivi->surfaces, link)
+               if (is == surf)
+                       return true;
+
+       return false;
+}
+
 void
 ivi_layout_activate(struct ivi_output *output, const char *app_id)
 {
@@ -579,9 +597,12 @@ ivi_layout_activate(struct ivi_output *output, const char *app_id)
                return;
        }
 
-       if (surf == output->active)
+       /* do not 're'-activate surfaces that are split or active */
+       if (surf == output->active ||
+           ivi_layout_surface_is_split_or_fs(surf))
                return;
 
+
        dsurf = surf->dsurface;
        view = surf->view;
        geom = weston_desktop_surface_get_geometry(dsurf);